3(z+1)+4(z-3)=5

Solution for 3(z+1)+4(z-3)=5 equation:

Simplifying
3(z + 1) + 4(z + -3) = 5

Reorder the terms:
3(1 + z) + 4(z + -3) = 5
(1 * 3 + z * 3) + 4(z + -3) = 5
(3 + 3z) + 4(z + -3) = 5

Reorder the terms:
3 + 3z + 4(-3 + z) = 5
3 + 3z + (-3 * 4 + z * 4) = 5
3 + 3z + (-12 + 4z) = 5

Reorder the terms:
3 + -12 + 3z + 4z = 5

Combine like terms: 3 + -12 = -9
-9 + 3z + 4z = 5

Combine like terms: 3z + 4z = 7z
-9 + 7z = 5

Solving
-9 + 7z = 5

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 7z = 5 + 9

Combine like terms: -9 + 9 = 0
0 + 7z = 5 + 9
7z = 5 + 9

Combine like terms: 5 + 9 = 14
7z = 14

Divide each side by '7'.
z = 2

Simplifying
z = 2