3(z+1)-2=19

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Solution for 3(z+1)-2=19 equation: 



3(z+1)-2=19

We move all terms to the left:

3(z+1)-2-(19)=0

We add all the numbers together, and all the variables

3(z+1)-21=0

We multiply parentheses

3z+3-21=0

We add all the numbers together, and all the variables

3z-18=0

We move all terms containing z to the left, all other terms to the right

3z=18

z=18/3

z=6

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