3(z+1)-2=3z+1

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Solution for 3(z+1)-2=3z+1 equation: 



3(z+1)-2=3z+1

We move all terms to the left:

3(z+1)-2-(3z+1)=0

We multiply parentheses

3z-(3z+1)+3-2=0

We get rid of parentheses

3z-3z-1+3-2=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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