3(z+1)=2(z-3)+2

Solution for 3(z+1)=2(z-3)+2 equation:

Simplifying
3(z + 1) = 2(z + -3) + 2

Reorder the terms:
3(1 + z) = 2(z + -3) + 2
(1 * 3 + z * 3) = 2(z + -3) + 2
(3 + 3z) = 2(z + -3) + 2

Reorder the terms:
3 + 3z = 2(-3 + z) + 2
3 + 3z = (-3 * 2 + z * 2) + 2
3 + 3z = (-6 + 2z) + 2

Reorder the terms:
3 + 3z = -6 + 2 + 2z

Combine like terms: -6 + 2 = -4
3 + 3z = -4 + 2z

Solving
3 + 3z = -4 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
3 + 3z + -2z = -4 + 2z + -2z

Combine like terms: 3z + -2z = 1z
3 + 1z = -4 + 2z + -2z

Combine like terms: 2z + -2z = 0
3 + 1z = -4 + 0
3 + 1z = -4

Add '-3' to each side of the equation.
3 + -3 + 1z = -4 + -3

Combine like terms: 3 + -3 = 0
0 + 1z = -4 + -3
1z = -4 + -3

Combine like terms: -4 + -3 = -7
1z = -7

Divide each side by '1'.
z = -7

Simplifying
z = -7