3(z+1)=4(z-1)

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Solution for 3(z+1)=4(z-1) equation: 



3(z+1)=4(z-1)

We move all terms to the left:

3(z+1)-(4(z-1))=0

We multiply parentheses

3z-(4(z-1))+3=0



We calculate terms in parentheses: -(4(z-1)), so:

4(z-1)

We multiply parentheses

4z-4

Back to the equation:

-(4z-4)



We get rid of parentheses

3z-4z+4+3=0

We add all the numbers together, and all the variables

-1z+7=0

We move all terms containing z to the left, all other terms to the right

-z=-7

z=-7/-1

z=+7

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