3(z+11)+4(z-3)=7(z+3)

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Solution for 3(z+11)+4(z-3)=7(z+3) equation: 



3(z+11)+4(z-3)=7(z+3)

We move all terms to the left:

3(z+11)+4(z-3)-(7(z+3))=0

We multiply parentheses

3z+4z-(7(z+3))+33-12=0



We calculate terms in parentheses: -(7(z+3)), so:

7(z+3)

We multiply parentheses

7z+21

Back to the equation:

-(7z+21)



We add all the numbers together, and all the variables

7z-(7z+21)+21=0

We get rid of parentheses

7z-7z-21+21=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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