3(z+12)-7z+2=2(19-2z)

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Solution for 3(z+12)-7z+2=2(19-2z) equation: 


Simplifying
3(z + 12) + -7z + 2 = 2(19 + -2z)

Reorder the terms:
3(12 + z) + -7z + 2 = 2(19 + -2z)
(12 * 3 + z * 3) + -7z + 2 = 2(19 + -2z)
(36 + 3z) + -7z + 2 = 2(19 + -2z)

Reorder the terms:
36 + 2 + 3z + -7z = 2(19 + -2z)

Combine like terms: 36 + 2 = 38
38 + 3z + -7z = 2(19 + -2z)

Combine like terms: 3z + -7z = -4z
38 + -4z = 2(19 + -2z)
38 + -4z = (19 * 2 + -2z * 2)
38 + -4z = (38 + -4z)

Add '-38' to each side of the equation.
38 + -38 + -4z = 38 + -38 + -4z

Combine like terms: 38 + -38 = 0
0 + -4z = 38 + -38 + -4z
-4z = 38 + -38 + -4z

Combine like terms: 38 + -38 = 0
-4z = 0 + -4z
-4z = -4z

Add '4z' to each side of the equation.
-4z + 4z = -4z + 4z

Combine like terms: -4z + 4z = 0
0 = -4z + 4z

Combine like terms: -4z + 4z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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