3(z+2)+4z=28-2(z-2)

Solution for 3(z+2)+4z=28-2(z-2) equation:

Simplifying
3(z + 2) + 4z = 28 + -2(z + -2)

Reorder the terms:
3(2 + z) + 4z = 28 + -2(z + -2)
(2 * 3 + z * 3) + 4z = 28 + -2(z + -2)
(6 + 3z) + 4z = 28 + -2(z + -2)

Combine like terms: 3z + 4z = 7z
6 + 7z = 28 + -2(z + -2)

Reorder the terms:
6 + 7z = 28 + -2(-2 + z)
6 + 7z = 28 + (-2 * -2 + z * -2)
6 + 7z = 28 + (4 + -2z)

Combine like terms: 28 + 4 = 32
6 + 7z = 32 + -2z

Solving
6 + 7z = 32 + -2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2z' to each side of the equation.
6 + 7z + 2z = 32 + -2z + 2z

Combine like terms: 7z + 2z = 9z
6 + 9z = 32 + -2z + 2z

Combine like terms: -2z + 2z = 0
6 + 9z = 32 + 0
6 + 9z = 32

Add '-6' to each side of the equation.
6 + -6 + 9z = 32 + -6

Combine like terms: 6 + -6 = 0
0 + 9z = 32 + -6
9z = 32 + -6

Combine like terms: 32 + -6 = 26
9z = 26

Divide each side by '9'.
z = 2.888888889

Simplifying
z = 2.888888889