3(z+2)-2(3z+1)=

Solution for 3(z+2)-2(3z+1)= equation:

Simplifying
3(z + 2) + -2(3z + 1) = 0

Reorder the terms:
3(2 + z) + -2(3z + 1) = 0
(2 * 3 + z * 3) + -2(3z + 1) = 0
(6 + 3z) + -2(3z + 1) = 0

Reorder the terms:
6 + 3z + -2(1 + 3z) = 0
6 + 3z + (1 * -2 + 3z * -2) = 0
6 + 3z + (-2 + -6z) = 0

Reorder the terms:
6 + -2 + 3z + -6z = 0

Combine like terms: 6 + -2 = 4
4 + 3z + -6z = 0

Combine like terms: 3z + -6z = -3z
4 + -3z = 0

Solving
4 + -3z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -3z = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -3z = 0 + -4
-3z = 0 + -4

Combine like terms: 0 + -4 = -4
-3z = -4

Divide each side by '-3'.
z = 1.333333333

Simplifying
z = 1.333333333