3(z+2)-7z=8(-0.5z+1)-2

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Solution for 3(z+2)-7z=8(-0.5z+1)-2 equation:


Simplifying
3(z + 2) + -7z = 8(-0.5z + 1) + -2

Reorder the terms:
3(2 + z) + -7z = 8(-0.5z + 1) + -2
(2 * 3 + z * 3) + -7z = 8(-0.5z + 1) + -2
(6 + 3z) + -7z = 8(-0.5z + 1) + -2

Combine like terms: 3z + -7z = -4z
6 + -4z = 8(-0.5z + 1) + -2

Reorder the terms:
6 + -4z = 8(1 + -0.5z) + -2
6 + -4z = (1 * 8 + -0.5z * 8) + -2
6 + -4z = (8 + -4z) + -2

Reorder the terms:
6 + -4z = 8 + -2 + -4z

Combine like terms: 8 + -2 = 6
6 + -4z = 6 + -4z

Add '-6' to each side of the equation.
6 + -6 + -4z = 6 + -6 + -4z

Combine like terms: 6 + -6 = 0
0 + -4z = 6 + -6 + -4z
-4z = 6 + -6 + -4z

Combine like terms: 6 + -6 = 0
-4z = 0 + -4z
-4z = -4z

Add '4z' to each side of the equation.
-4z + 4z = -4z + 4z

Combine like terms: -4z + 4z = 0
0 = -4z + 4z

Combine like terms: -4z + 4z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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