3(z+2)=15z-30

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Solution for 3(z+2)=15z-30 equation: 



3(z+2)=15z-30

We move all terms to the left:

3(z+2)-(15z-30)=0

We multiply parentheses

3z-(15z-30)+6=0

We get rid of parentheses

3z-15z+30+6=0

We add all the numbers together, and all the variables

-12z+36=0

We move all terms containing z to the left, all other terms to the right

-12z=-36

z=-36/-12

z=+3

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