3(z+2)=2(z-1)

Solution for 3(z+2)=2(z-1) equation:

Simplifying
3(z + 2) = 2(z + -1)

Reorder the terms:
3(2 + z) = 2(z + -1)
(2 * 3 + z * 3) = 2(z + -1)
(6 + 3z) = 2(z + -1)

Reorder the terms:
6 + 3z = 2(-1 + z)
6 + 3z = (-1 * 2 + z * 2)
6 + 3z = (-2 + 2z)

Solving
6 + 3z = -2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
6 + 3z + -2z = -2 + 2z + -2z

Combine like terms: 3z + -2z = 1z
6 + 1z = -2 + 2z + -2z

Combine like terms: 2z + -2z = 0
6 + 1z = -2 + 0
6 + 1z = -2

Add '-6' to each side of the equation.
6 + -6 + 1z = -2 + -6

Combine like terms: 6 + -6 = 0
0 + 1z = -2 + -6
1z = -2 + -6

Combine like terms: -2 + -6 = -8
1z = -8

Divide each side by '1'.
z = -8

Simplifying
z = -8