3(z+2)=27

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Solution for 3(z+2)=27 equation: 



3(z+2)=27

We move all terms to the left:

3(z+2)-(27)=0

We multiply parentheses

3z+6-27=0

We add all the numbers together, and all the variables

3z-21=0

We move all terms containing z to the left, all other terms to the right

3z=21

z=21/3

z=7

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