3(z+2)=42+3-2(3z+1)

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Solution for 3(z+2)=42+3-2(3z+1) equation:


3(z+2)=42+3-2(3z+1)

We simplify the equation to the form, which is simple to understand 
3(z+2)=42+3-2(3z+1)

Reorder the terms in parentheses
+(+3z+6)=42+3-2*(3z+1)

Remove unnecessary parentheses
+3z+6=+42+3-2+*(+3z+1+)

Reorder the terms in parentheses
+3z+6=42+3+(-6z-2)

Remove unnecessary parentheses
+3z+6=+42+3-6z-2

We move all terms containing z to the left and all other terms to the right. 
+3z+6z=+42+3-2-6

We simplify left and right side of the equation. 
+9z=+37

We divide both sides of the equation by 9 to get z. 
z=4.11111111111

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