3(z+2)=5z-6

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Solution for 3(z+2)=5z-6 equation:



3(z+2)=5z-6
We move all terms to the left:
3(z+2)-(5z-6)=0
We multiply parentheses
3z-(5z-6)+6=0
We get rid of parentheses
3z-5z+6+6=0
We add all the numbers together, and all the variables
-2z+12=0
We move all terms containing z to the left, all other terms to the right
-2z=-12
z=-12/-2
z=+6

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