3(z+2)=8z+1

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Solution for 3(z+2)=8z+1 equation:



3(z+2)=8z+1
We move all terms to the left:
3(z+2)-(8z+1)=0
We multiply parentheses
3z-(8z+1)+6=0
We get rid of parentheses
3z-8z-1+6=0
We add all the numbers together, and all the variables
-5z+5=0
We move all terms containing z to the left, all other terms to the right
-5z=-5
z=-5/-5
z=1

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