3(z+2)=8z+1

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Solution for 3(z+2)=8z+1 equation: 



3(z+2)=8z+1

We move all terms to the left:

3(z+2)-(8z+1)=0

We multiply parentheses

3z-(8z+1)+6=0

We get rid of parentheses

3z-8z-1+6=0

We add all the numbers together, and all the variables

-5z+5=0

We move all terms containing z to the left, all other terms to the right

-5z=-5

z=-5/-5

z=1

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