3(z+3)-2=4(z-1)

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Solution for 3(z+3)-2=4(z-1) equation:


Simplifying
3(z + 3) + -2 = 4(z + -1)

Reorder the terms:
3(3 + z) + -2 = 4(z + -1)
(3 * 3 + z * 3) + -2 = 4(z + -1)
(9 + 3z) + -2 = 4(z + -1)

Reorder the terms:
9 + -2 + 3z = 4(z + -1)

Combine like terms: 9 + -2 = 7
7 + 3z = 4(z + -1)

Reorder the terms:
7 + 3z = 4(-1 + z)
7 + 3z = (-1 * 4 + z * 4)
7 + 3z = (-4 + 4z)

Solving
7 + 3z = -4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
7 + 3z + -4z = -4 + 4z + -4z

Combine like terms: 3z + -4z = -1z
7 + -1z = -4 + 4z + -4z

Combine like terms: 4z + -4z = 0
7 + -1z = -4 + 0
7 + -1z = -4

Add '-7' to each side of the equation.
7 + -7 + -1z = -4 + -7

Combine like terms: 7 + -7 = 0
0 + -1z = -4 + -7
-1z = -4 + -7

Combine like terms: -4 + -7 = -11
-1z = -11

Divide each side by '-1'.
z = 11

Simplifying
z = 11

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