3(z+3)=32

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Solution for 3(z+3)=32 equation: 



3(z+3)=32

We move all terms to the left:

3(z+3)-(32)=0

We multiply parentheses

3z+9-32=0

We add all the numbers together, and all the variables

3z-23=0

We move all terms containing z to the left, all other terms to the right

3z=23

z=23/3

z=7+2/3

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