3(z+3)=6(2z-4)

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Solution for 3(z+3)=6(2z-4) equation: 



3(z+3)=6(2z-4)

We move all terms to the left:

3(z+3)-(6(2z-4))=0

We multiply parentheses

3z-(6(2z-4))+9=0



We calculate terms in parentheses: -(6(2z-4)), so:

6(2z-4)

We multiply parentheses

12z-24

Back to the equation:

-(12z-24)



We get rid of parentheses

3z-12z+24+9=0

We add all the numbers together, and all the variables

-9z+33=0

We move all terms containing z to the left, all other terms to the right

-9z=-33

z=-33/-9

z=3+2/3

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