3(z+3)=7+3z+6-2

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Solution for 3(z+3)=7+3z+6-2 equation: 



3(z+3)=7+3z+6-2

We move all terms to the left:

3(z+3)-(7+3z+6-2)=0

We add all the numbers together, and all the variables

3(z+3)-(3z+11)=0

We multiply parentheses

3z-(3z+11)+9=0

We get rid of parentheses

3z-3z-11+9=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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