3(z+3)=7+6-z

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Solution for 3(z+3)=7+6-z equation: 



3(z+3)=7+6-z

We move all terms to the left:

3(z+3)-(7+6-z)=0

We add all the numbers together, and all the variables

3(z+3)-(-1z+13)=0

We multiply parentheses

3z-(-1z+13)+9=0

We get rid of parentheses

3z+1z-13+9=0

We add all the numbers together, and all the variables

4z-4=0

We move all terms containing z to the left, all other terms to the right

4z=4

z=4/4

z=1

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