3(z+3)=7+6-z

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Solution for 3(z+3)=7+6-z equation:



3(z+3)=7+6-z
We move all terms to the left:
3(z+3)-(7+6-z)=0
We add all the numbers together, and all the variables
3(z+3)-(-1z+13)=0
We multiply parentheses
3z-(-1z+13)+9=0
We get rid of parentheses
3z+1z-13+9=0
We add all the numbers together, and all the variables
4z-4=0
We move all terms containing z to the left, all other terms to the right
4z=4
z=4/4
z=1

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