3(z+3)=7=3z+6-z

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Solution for 3(z+3)=7=3z+6-z equation: 



3(z+3)=7=3z+6-z

We move all terms to the left:

3(z+3)-(7)=0

We multiply parentheses

3z+9-7=0

We add all the numbers together, and all the variables

3z+2=0

We move all terms containing z to the left, all other terms to the right

3z=-2

z=-2/3

z=-2/3

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