3(z+4)+(z-2)*6=15

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Solution for 3(z+4)+(z-2)*6=15 equation: 


Simplifying
3(z + 4) + (z + -2) * 6 = 15

Reorder the terms:
3(4 + z) + (z + -2) * 6 = 15
(4 * 3 + z * 3) + (z + -2) * 6 = 15
(12 + 3z) + (z + -2) * 6 = 15

Reorder the terms:
12 + 3z + (-2 + z) * 6 = 15

Reorder the terms for easier multiplication:
12 + 3z + 6(-2 + z) = 15
12 + 3z + (-2 * 6 + z * 6) = 15
12 + 3z + (-12 + 6z) = 15

Reorder the terms:
12 + -12 + 3z + 6z = 15

Combine like terms: 12 + -12 = 0
0 + 3z + 6z = 15
3z + 6z = 15

Combine like terms: 3z + 6z = 9z
9z = 15

Solving
9z = 15

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Divide each side by '9'.
z = 1.666666667

Simplifying
z = 1.666666667

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