3(z+4)-6=6(5-z)

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Solution for 3(z+4)-6=6(5-z) equation:



3(z+4)-6=6(5-z)
We move all terms to the left:
3(z+4)-6-(6(5-z))=0
We add all the numbers together, and all the variables
3(z+4)-(6(-1z+5))-6=0
We multiply parentheses
3z-(6(-1z+5))+12-6=0
We calculate terms in parentheses: -(6(-1z+5)), so:
6(-1z+5)
We multiply parentheses
-6z+30
Back to the equation:
-(-6z+30)
We add all the numbers together, and all the variables
3z-(-6z+30)+6=0
We get rid of parentheses
3z+6z-30+6=0
We add all the numbers together, and all the variables
9z-24=0
We move all terms containing z to the left, all other terms to the right
9z=24
z=24/9
z=2+2/3

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