3(z+4)-z=6z

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Solution for 3(z+4)-z=6z equation: 



3(z+4)-z=6z

We move all terms to the left:

3(z+4)-z-(6z)=0

We add all the numbers together, and all the variables

-7z+3(z+4)=0

We multiply parentheses

-7z+3z+12=0

We add all the numbers together, and all the variables

-4z+12=0

We move all terms containing z to the left, all other terms to the right

-4z=-12

z=-12/-4

z=+3

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