3(z+4)/7=6

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Solution for 3(z+4)/7=6 equation: 



3(z+4)/7=6

We move all terms to the left:

3(z+4)/7-(6)=0

We multiply all the terms by the denominator


3(z+4)-6*7=0

We add all the numbers together, and all the variables

3(z+4)-42=0

We multiply parentheses

3z+12-42=0

We add all the numbers together, and all the variables

3z-30=0

We move all terms containing z to the left, all other terms to the right

3z=30

z=30/3

z=10

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