3(z+4)=3(z+4)

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Solution for 3(z+4)=3(z+4) equation:


Simplifying
3(z + 4) = 3(z + 4)

Reorder the terms:
3(4 + z) = 3(z + 4)
(4 * 3 + z * 3) = 3(z + 4)
(12 + 3z) = 3(z + 4)

Reorder the terms:
12 + 3z = 3(4 + z)
12 + 3z = (4 * 3 + z * 3)
12 + 3z = (12 + 3z)

Add '-12' to each side of the equation.
12 + -12 + 3z = 12 + -12 + 3z

Combine like terms: 12 + -12 = 0
0 + 3z = 12 + -12 + 3z
3z = 12 + -12 + 3z

Combine like terms: 12 + -12 = 0
3z = 0 + 3z
3z = 3z

Add '-3z' to each side of the equation.
3z + -3z = 3z + -3z

Combine like terms: 3z + -3z = 0
0 = 3z + -3z

Combine like terms: 3z + -3z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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