3(z+5)+3z=135

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Solution for 3(z+5)+3z=135 equation: 



3(z+5)+3z=135

We move all terms to the left:

3(z+5)+3z-(135)=0

We add all the numbers together, and all the variables

3z+3(z+5)-135=0

We multiply parentheses

3z+3z+15-135=0

We add all the numbers together, and all the variables

6z-120=0

We move all terms containing z to the left, all other terms to the right

6z=120

z=120/6

z=20

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