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3(z+5)=2z+15+z3(z+5)=2z+15
We move all terms to the left:
3(z+5)-(2z+15+z3(z+5))=0
We multiply parentheses
3z-(2z+15+z3(z+5))+15=0
We calculate terms in parentheses: -(2z+15+z3(z+5)), so:
2z+15+z3(z+5)
determiningTheFunctionDomain 2z+z3(z+5)+15
We multiply parentheses
z^4+5z^3+2z+15
We do not support ezpression: z^4
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