3(z+5)=2z-4+zC

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Solution for 3(z+5)=2z-4+zC equation: 



3(z+5)=2z-4+z

We move all terms to the left:

3(z+5)-(2z-4+z)=0

We add all the numbers together, and all the variables

3(z+5)-(3z-4)=0

We multiply parentheses

3z-(3z-4)+15=0

We get rid of parentheses

3z-3z+4+15=0

We add all the numbers together, and all the variables

19!=0

There is no solution for this equation

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