3(z+5)=2z-4C

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Solution for 3(z+5)=2z-4C equation: 



3(z+5)=2z-4

We move all terms to the left:

3(z+5)-(2z-4)=0

We multiply parentheses

3z-(2z-4)+15=0

We get rid of parentheses

3z-2z+4+15=0

We add all the numbers together, and all the variables

z+19=0

We move all terms containing z to the left, all other terms to the right

z=-19

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