3(z+6)+4(8-z)-12=30

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Solution for 3(z+6)+4(8-z)-12=30 equation: 



3(z+6)+4(8-z)-12=30

We move all terms to the left:

3(z+6)+4(8-z)-12-(30)=0

We add all the numbers together, and all the variables

3(z+6)+4(-1z+8)-12-30=0

We add all the numbers together, and all the variables

3(z+6)+4(-1z+8)-42=0

We multiply parentheses

3z-4z+18+32-42=0

We add all the numbers together, and all the variables

-1z+8=0

We move all terms containing z to the left, all other terms to the right

-z=-8

z=-8/-1

z=+8

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