3(z+6)=19(18z+27)

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Solution for 3(z+6)=19(18z+27) equation:



3(z+6)=19(18z+27)
We move all terms to the left:
3(z+6)-(19(18z+27))=0
We multiply parentheses
3z-(19(18z+27))+18=0
We calculate terms in parentheses: -(19(18z+27)), so:
19(18z+27)
We multiply parentheses
342z+513
Back to the equation:
-(342z+513)
We get rid of parentheses
3z-342z-513+18=0
We add all the numbers together, and all the variables
-339z-495=0
We move all terms containing z to the left, all other terms to the right
-339z=495
z=495/-339
z=-1+52/113

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