3(z+6)=2(24-z)

Solution for 3(z+6)=2(24-z) equation:

3(z+6)=2(24-z)

We move all terms to the left:

3(z+6)-(2(24-z))=0

We add all the numbers together, and all the variables

3(z+6)-(2(-1z+24))=0

We multiply parentheses

3z-(2(-1z+24))+18=0


We calculate terms in parentheses: -(2(-1z+24)), so:

2(-1z+24)

We multiply parentheses

-2z+48

Back to the equation:

-(-2z+48)


We get rid of parentheses

3z+2z-48+18=0

We add all the numbers together, and all the variables

5z-30=0

We move all terms containing z to the left, all other terms to the right

5z=30

z=30/5

z=6