3(z-1)-2z=3(z+4)-3(z-1)

Solution for 3(z-1)-2z=3(z+4)-3(z-1) equation:

3(z-1)-2z=3(z+4)-3(z-1)

We move all terms to the left:

3(z-1)-2z-(3(z+4)-3(z-1))=0

We add all the numbers together, and all the variables

-2z+3(z-1)-(3(z+4)-3(z-1))=0

We multiply parentheses

-2z+3z-(3(z+4)-3(z-1))-3=0


We calculate terms in parentheses: -(3(z+4)-3(z-1)), so:

3(z+4)-3(z-1)

We multiply parentheses

3z-3z+12+3

We add all the numbers together, and all the variables

15

Back to the equation:

-(15)


We add all the numbers together, and all the variables

z-18=0

We move all terms containing z to the left, all other terms to the right

z=18