3(z-1)=2(z+1)

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Solution for 3(z-1)=2(z+1) equation: 



3(z-1)=2(z+1)

We move all terms to the left:

3(z-1)-(2(z+1))=0

We multiply parentheses

3z-(2(z+1))-3=0



We calculate terms in parentheses: -(2(z+1)), so:

2(z+1)

We multiply parentheses

2z+2

Back to the equation:

-(2z+2)



We get rid of parentheses

3z-2z-2-3=0

We add all the numbers together, and all the variables

z-5=0

We move all terms containing z to the left, all other terms to the right

z=5

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