3(z-1)=5(z+2)-3

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Solution for 3(z-1)=5(z+2)-3 equation:


Simplifying
3(z + -1) = 5(z + 2) + -3

Reorder the terms:
3(-1 + z) = 5(z + 2) + -3
(-1 * 3 + z * 3) = 5(z + 2) + -3
(-3 + 3z) = 5(z + 2) + -3

Reorder the terms:
-3 + 3z = 5(2 + z) + -3
-3 + 3z = (2 * 5 + z * 5) + -3
-3 + 3z = (10 + 5z) + -3

Reorder the terms:
-3 + 3z = 10 + -3 + 5z

Combine like terms: 10 + -3 = 7
-3 + 3z = 7 + 5z

Solving
-3 + 3z = 7 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-3 + 3z + -5z = 7 + 5z + -5z

Combine like terms: 3z + -5z = -2z
-3 + -2z = 7 + 5z + -5z

Combine like terms: 5z + -5z = 0
-3 + -2z = 7 + 0
-3 + -2z = 7

Add '3' to each side of the equation.
-3 + 3 + -2z = 7 + 3

Combine like terms: -3 + 3 = 0
0 + -2z = 7 + 3
-2z = 7 + 3

Combine like terms: 7 + 3 = 10
-2z = 10

Divide each side by '-2'.
z = -5

Simplifying
z = -5

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