3(z-1)=z+15

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Solution for 3(z-1)=z+15 equation: 



3(z-1)=z+15

We move all terms to the left:

3(z-1)-(z+15)=0

We multiply parentheses

3z-(z+15)-3=0

We get rid of parentheses

3z-z-15-3=0

We add all the numbers together, and all the variables

2z-18=0

We move all terms containing z to the left, all other terms to the right

2z=18

z=18/2

z=9

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