3(z-12)=42

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Solution for 3(z-12)=42 equation: 



3(z-12)=42

We move all terms to the left:

3(z-12)-(42)=0

We multiply parentheses

3z-36-42=0

We add all the numbers together, and all the variables

3z-78=0

We move all terms containing z to the left, all other terms to the right

3z=78

z=78/3

z=26

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