3(z-2)+2(2z-4)=z-2

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Solution for 3(z-2)+2(2z-4)=z-2 equation:


Simplifying
3(z + -2) + 2(2z + -4) = z + -2

Reorder the terms:
3(-2 + z) + 2(2z + -4) = z + -2
(-2 * 3 + z * 3) + 2(2z + -4) = z + -2
(-6 + 3z) + 2(2z + -4) = z + -2

Reorder the terms:
-6 + 3z + 2(-4 + 2z) = z + -2
-6 + 3z + (-4 * 2 + 2z * 2) = z + -2
-6 + 3z + (-8 + 4z) = z + -2

Reorder the terms:
-6 + -8 + 3z + 4z = z + -2

Combine like terms: -6 + -8 = -14
-14 + 3z + 4z = z + -2

Combine like terms: 3z + 4z = 7z
-14 + 7z = z + -2

Reorder the terms:
-14 + 7z = -2 + z

Solving
-14 + 7z = -2 + z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-14 + 7z + -1z = -2 + z + -1z

Combine like terms: 7z + -1z = 6z
-14 + 6z = -2 + z + -1z

Combine like terms: z + -1z = 0
-14 + 6z = -2 + 0
-14 + 6z = -2

Add '14' to each side of the equation.
-14 + 14 + 6z = -2 + 14

Combine like terms: -14 + 14 = 0
0 + 6z = -2 + 14
6z = -2 + 14

Combine like terms: -2 + 14 = 12
6z = 12

Divide each side by '6'.
z = 2

Simplifying
z = 2

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