3(z-2)+26=5(z+4)

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Solution for 3(z-2)+26=5(z+4) equation:


Simplifying
3(z + -2) + 26 = 5(z + 4)

Reorder the terms:
3(-2 + z) + 26 = 5(z + 4)
(-2 * 3 + z * 3) + 26 = 5(z + 4)
(-6 + 3z) + 26 = 5(z + 4)

Reorder the terms:
-6 + 26 + 3z = 5(z + 4)

Combine like terms: -6 + 26 = 20
20 + 3z = 5(z + 4)

Reorder the terms:
20 + 3z = 5(4 + z)
20 + 3z = (4 * 5 + z * 5)
20 + 3z = (20 + 5z)

Add '-20' to each side of the equation.
20 + -20 + 3z = 20 + -20 + 5z

Combine like terms: 20 + -20 = 0
0 + 3z = 20 + -20 + 5z
3z = 20 + -20 + 5z

Combine like terms: 20 + -20 = 0
3z = 0 + 5z
3z = 5z

Solving
3z = 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
3z + -5z = 5z + -5z

Combine like terms: 3z + -5z = -2z
-2z = 5z + -5z

Combine like terms: 5z + -5z = 0
-2z = 0

Divide each side by '-2'.
z = 0

Simplifying
z = 0

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