3(z-2)+2z=20

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Solution for 3(z-2)+2z=20 equation: 



3(z-2)+2z=20

We move all terms to the left:

3(z-2)+2z-(20)=0

We add all the numbers together, and all the variables

2z+3(z-2)-20=0

We multiply parentheses

2z+3z-6-20=0

We add all the numbers together, and all the variables

5z-26=0

We move all terms containing z to the left, all other terms to the right

5z=26

z=26/5

z=5+1/5

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