3(z-2)+6=5(z+4z)

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Solution for 3(z-2)+6=5(z+4z) equation: 



3(z-2)+6=5(z+4z)

We move all terms to the left:

3(z-2)+6-(5(z+4z))=0

We add all the numbers together, and all the variables

3(z-2)-(5(+5z))+6=0

We multiply parentheses

3z-(5(+5z))-6+6=0



We calculate terms in parentheses: -(5(+5z)), so:

5(+5z)

We multiply parentheses

25z

Back to the equation:

-(25z)



We add all the numbers together, and all the variables

-22z=0

z=0/-22

z=0

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