3(z-2)-(3z-1)=2(2z-4)-5

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Solution for 3(z-2)-(3z-1)=2(2z-4)-5 equation:


3(z-2)-(3z-1)=2(2z-4)-5

We simplify the equation to the form, which is simple to understand 
3(z-2)-(3z-1)=2(2z-4)-5

Reorder the terms in parentheses
+(+3z-6)-(3z-1)=2*(2z-4)-5

Remove unnecessary parentheses
+3z-6-(+3z-1+)=+2+*(+2z-4+)-5

Remove unnecessary parentheses
+3z-6-3z+1=2*(2z-4)-5

Reorder the terms in parentheses
+3z-6-3z+1=+(+4z-8)-5

Remove unnecessary parentheses
+3z-6-3z+1=+4z-8-5

We move all terms containing z to the left and all other terms to the right. 
+3z-3z-4z=-8-5+6-1

We simplify left and right side of the equation. 
-4z=-8

We divide both sides of the equation by -4 to get z. 
z=2

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