3(z-2)-11z=-7(z+2)+14

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Solution for 3(z-2)-11z=-7(z+2)+14 equation: 



3(z-2)-11z=-7(z+2)+14

We move all terms to the left:

3(z-2)-11z-(-7(z+2)+14)=0

We add all the numbers together, and all the variables

-11z+3(z-2)-(-7(z+2)+14)=0

We multiply parentheses

-11z+3z-(-7(z+2)+14)-6=0



We calculate terms in parentheses: -(-7(z+2)+14), so:

-7(z+2)+14

We multiply parentheses

-7z-14+14

We add all the numbers together, and all the variables

-7z

Back to the equation:

-(-7z)



We add all the numbers together, and all the variables

-8z-(-7z)-6=0

We get rid of parentheses

-8z+7z-6=0

We add all the numbers together, and all the variables

-1z-6=0

We move all terms containing z to the left, all other terms to the right

-z=6

z=6/-1

z=-6

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