3(z-2)-1=4(z-3)

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Solution for 3(z-2)-1=4(z-3) equation:


Simplifying
3(z + -2) + -1 = 4(z + -3)

Reorder the terms:
3(-2 + z) + -1 = 4(z + -3)
(-2 * 3 + z * 3) + -1 = 4(z + -3)
(-6 + 3z) + -1 = 4(z + -3)

Reorder the terms:
-6 + -1 + 3z = 4(z + -3)

Combine like terms: -6 + -1 = -7
-7 + 3z = 4(z + -3)

Reorder the terms:
-7 + 3z = 4(-3 + z)
-7 + 3z = (-3 * 4 + z * 4)
-7 + 3z = (-12 + 4z)

Solving
-7 + 3z = -12 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-7 + 3z + -4z = -12 + 4z + -4z

Combine like terms: 3z + -4z = -1z
-7 + -1z = -12 + 4z + -4z

Combine like terms: 4z + -4z = 0
-7 + -1z = -12 + 0
-7 + -1z = -12

Add '7' to each side of the equation.
-7 + 7 + -1z = -12 + 7

Combine like terms: -7 + 7 = 0
0 + -1z = -12 + 7
-1z = -12 + 7

Combine like terms: -12 + 7 = -5
-1z = -5

Divide each side by '-1'.
z = 5

Simplifying
z = 5

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