3(z-2)-2z=20

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Solution for 3(z-2)-2z=20 equation: 



3(z-2)-2z=20

We move all terms to the left:

3(z-2)-2z-(20)=0

We add all the numbers together, and all the variables

-2z+3(z-2)-20=0

We multiply parentheses

-2z+3z-6-20=0

We add all the numbers together, and all the variables

z-26=0

We move all terms containing z to the left, all other terms to the right

z=26

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