3(z-2)-5=4(2z+1)+5

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Solution for 3(z-2)-5=4(2z+1)+5 equation: 



3(z-2)-5=4(2z+1)+5

We move all terms to the left:

3(z-2)-5-(4(2z+1)+5)=0

We multiply parentheses

3z-(4(2z+1)+5)-6-5=0



We calculate terms in parentheses: -(4(2z+1)+5), so:

4(2z+1)+5

We multiply parentheses

8z+4+5

We add all the numbers together, and all the variables

8z+9

Back to the equation:

-(8z+9)



We add all the numbers together, and all the variables

3z-(8z+9)-11=0

We get rid of parentheses

3z-8z-9-11=0

We add all the numbers together, and all the variables

-5z-20=0

We move all terms containing z to the left, all other terms to the right

-5z=20

z=20/-5

z=-4

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