3(z-2)-5=4(z-7)

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Solution for 3(z-2)-5=4(z-7) equation:


Simplifying
3(z + -2) + -5 = 4(z + -7)

Reorder the terms:
3(-2 + z) + -5 = 4(z + -7)
(-2 * 3 + z * 3) + -5 = 4(z + -7)
(-6 + 3z) + -5 = 4(z + -7)

Reorder the terms:
-6 + -5 + 3z = 4(z + -7)

Combine like terms: -6 + -5 = -11
-11 + 3z = 4(z + -7)

Reorder the terms:
-11 + 3z = 4(-7 + z)
-11 + 3z = (-7 * 4 + z * 4)
-11 + 3z = (-28 + 4z)

Solving
-11 + 3z = -28 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-11 + 3z + -4z = -28 + 4z + -4z

Combine like terms: 3z + -4z = -1z
-11 + -1z = -28 + 4z + -4z

Combine like terms: 4z + -4z = 0
-11 + -1z = -28 + 0
-11 + -1z = -28

Add '11' to each side of the equation.
-11 + 11 + -1z = -28 + 11

Combine like terms: -11 + 11 = 0
0 + -1z = -28 + 11
-1z = -28 + 11

Combine like terms: -28 + 11 = -17
-1z = -17

Divide each side by '-1'.
z = 17

Simplifying
z = 17

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