3(z-2)=3(2z+4)238

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Solution for 3(z-2)=3(2z+4)238 equation: 



3(z-2)=3(2z+4)238

We move all terms to the left:

3(z-2)-(3(2z+4)238)=0

We multiply parentheses

3z-(3(2z+4)238)-6=0



We calculate terms in parentheses: -(3(2z+4)238), so:

3(2z+4)238

We multiply parentheses

1428z+2856

Back to the equation:

-(1428z+2856)



We get rid of parentheses

3z-1428z-2856-6=0

We add all the numbers together, and all the variables

-1425z-2862=0

We move all terms containing z to the left, all other terms to the right

-1425z=2862

z=2862/-1425

z=-2+4/475

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